2x^2+5x-4=x^2+3x-7

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Solution for 2x^2+5x-4=x^2+3x-7 equation: 



2x^2+5x-4=x^2+3x-7

We move all terms to the left:

2x^2+5x-4-(x^2+3x-7)=0

We get rid of parentheses

2x^2-x^2+5x-3x+7-4=0

We add all the numbers together, and all the variables

x^2+2x+3=0

a = 1; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation

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